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k^2-4k-192=0
a = 1; b = -4; c = -192;
Δ = b2-4ac
Δ = -42-4·1·(-192)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*1}=\frac{-24}{2} =-12 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*1}=\frac{32}{2} =16 $
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